Integrand size = 23, antiderivative size = 181 \[ \int (d \sec (e+f x))^m (a+b \tan (e+f x))^n \, dx=\frac {b \operatorname {AppellF1}\left (1+n,1-\frac {m}{2},1-\frac {m}{2},2+n,\frac {a+b \tan (e+f x)}{a+\sqrt {-b^2}},\frac {a+b \tan (e+f x)}{a-\sqrt {-b^2}}\right ) (d \sec (e+f x))^m (a+b \tan (e+f x))^{1+n} \left (1+\frac {a+b \tan (e+f x)}{-a+\sqrt {-b^2}}\right )^{-m/2} \left (1-\frac {a+b \tan (e+f x)}{a+\sqrt {-b^2}}\right )^{-m/2}}{\left (a^2+b^2\right ) f (1+n)} \]
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Time = 0.22 (sec) , antiderivative size = 187, normalized size of antiderivative = 1.03, number of steps used = 3, number of rules used = 3, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.130, Rules used = {3593, 774, 138} \[ \int (d \sec (e+f x))^m (a+b \tan (e+f x))^n \, dx=\frac {\cos ^2(e+f x) (d \sec (e+f x))^m \left (1-\frac {a+b \tan (e+f x)}{a-\sqrt {-b^2}}\right )^{1-\frac {m}{2}} \left (1-\frac {a+b \tan (e+f x)}{a+\sqrt {-b^2}}\right )^{1-\frac {m}{2}} (a+b \tan (e+f x))^{n+1} \operatorname {AppellF1}\left (n+1,1-\frac {m}{2},1-\frac {m}{2},n+2,\frac {a+b \tan (e+f x)}{a-\sqrt {-b^2}},\frac {a+b \tan (e+f x)}{a+\sqrt {-b^2}}\right )}{b f (n+1)} \]
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Rule 138
Rule 774
Rule 3593
Rubi steps \begin{align*} \text {integral}& = \frac {\left ((d \sec (e+f x))^m \sec ^2(e+f x)^{-m/2}\right ) \text {Subst}\left (\int (a+x)^n \left (1+\frac {x^2}{b^2}\right )^{-1+\frac {m}{2}} \, dx,x,b \tan (e+f x)\right )}{b f} \\ & = \frac {\left (\cos ^2(e+f x) (d \sec (e+f x))^m \left (1-\frac {a+b \tan (e+f x)}{a-\frac {b^2}{\sqrt {-b^2}}}\right )^{1-\frac {m}{2}} \left (1-\frac {a+b \tan (e+f x)}{a+\frac {b^2}{\sqrt {-b^2}}}\right )^{1-\frac {m}{2}}\right ) \text {Subst}\left (\int x^n \left (1-\frac {x}{a-\sqrt {-b^2}}\right )^{-1+\frac {m}{2}} \left (1-\frac {x}{a+\sqrt {-b^2}}\right )^{-1+\frac {m}{2}} \, dx,x,a+b \tan (e+f x)\right )}{b f} \\ & = \frac {\operatorname {AppellF1}\left (1+n,1-\frac {m}{2},1-\frac {m}{2},2+n,\frac {a+b \tan (e+f x)}{a-\sqrt {-b^2}},\frac {a+b \tan (e+f x)}{a+\sqrt {-b^2}}\right ) \cos ^2(e+f x) (d \sec (e+f x))^m (a+b \tan (e+f x))^{1+n} \left (1-\frac {a+b \tan (e+f x)}{a-\sqrt {-b^2}}\right )^{1-\frac {m}{2}} \left (1-\frac {a+b \tan (e+f x)}{a+\sqrt {-b^2}}\right )^{1-\frac {m}{2}}}{b f (1+n)} \\ \end{align*}
Result contains complex when optimal does not.
Time = 10.00 (sec) , antiderivative size = 699, normalized size of antiderivative = 3.86 \[ \int (d \sec (e+f x))^m (a+b \tan (e+f x))^n \, dx=\frac {2 \operatorname {AppellF1}\left (1+n,1-\frac {m}{2},1-\frac {m}{2},2+n,\frac {a+b \tan (e+f x)}{a-i b},\frac {a+b \tan (e+f x)}{a+i b}\right ) (d \sec (e+f x))^m (a+b \tan (e+f x))^{1+n}}{f \left (2 b \operatorname {AppellF1}\left (1+n,1-\frac {m}{2},1-\frac {m}{2},2+n,\frac {a+b \tan (e+f x)}{a-i b},\frac {a+b \tan (e+f x)}{a+i b}\right ) \sec ^2(e+f x)+2 n \operatorname {AppellF1}\left (1+n,1-\frac {m}{2},1-\frac {m}{2},2+n,\frac {a+b \tan (e+f x)}{a-i b},\frac {a+b \tan (e+f x)}{a+i b}\right ) (b-a \tan (e+f x))-\frac {b (-2+m) (1+n) \left ((a-i b) \operatorname {AppellF1}\left (2+n,1-\frac {m}{2},2-\frac {m}{2},3+n,\frac {a+b \tan (e+f x)}{a-i b},\frac {a+b \tan (e+f x)}{a+i b}\right )+(a+i b) \operatorname {AppellF1}\left (2+n,2-\frac {m}{2},1-\frac {m}{2},3+n,\frac {a+b \tan (e+f x)}{a-i b},\frac {a+b \tan (e+f x)}{a+i b}\right )\right ) \sec ^2(e+f x) (a+b \tan (e+f x))}{(a-i b) (a+i b) (2+n)}+2 (m+n) \operatorname {AppellF1}\left (1+n,1-\frac {m}{2},1-\frac {m}{2},2+n,\frac {a+b \tan (e+f x)}{a-i b},\frac {a+b \tan (e+f x)}{a+i b}\right ) \tan (e+f x) (a+b \tan (e+f x))-\frac {m \operatorname {AppellF1}\left (1+n,1-\frac {m}{2},1-\frac {m}{2},2+n,\frac {a+b \tan (e+f x)}{a-i b},\frac {a+b \tan (e+f x)}{a+i b}\right ) \sec ^2(e+f x) (a+b \tan (e+f x))}{-i+\tan (e+f x)}-\frac {m \operatorname {AppellF1}\left (1+n,1-\frac {m}{2},1-\frac {m}{2},2+n,\frac {a+b \tan (e+f x)}{a-i b},\frac {a+b \tan (e+f x)}{a+i b}\right ) \sec ^2(e+f x) (a+b \tan (e+f x))}{i+\tan (e+f x)}\right )} \]
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\[\int \left (d \sec \left (f x +e \right )\right )^{m} \left (a +b \tan \left (f x +e \right )\right )^{n}d x\]
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\[ \int (d \sec (e+f x))^m (a+b \tan (e+f x))^n \, dx=\int { \left (d \sec \left (f x + e\right )\right )^{m} {\left (b \tan \left (f x + e\right ) + a\right )}^{n} \,d x } \]
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\[ \int (d \sec (e+f x))^m (a+b \tan (e+f x))^n \, dx=\int \left (d \sec {\left (e + f x \right )}\right )^{m} \left (a + b \tan {\left (e + f x \right )}\right )^{n}\, dx \]
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\[ \int (d \sec (e+f x))^m (a+b \tan (e+f x))^n \, dx=\int { \left (d \sec \left (f x + e\right )\right )^{m} {\left (b \tan \left (f x + e\right ) + a\right )}^{n} \,d x } \]
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\[ \int (d \sec (e+f x))^m (a+b \tan (e+f x))^n \, dx=\int { \left (d \sec \left (f x + e\right )\right )^{m} {\left (b \tan \left (f x + e\right ) + a\right )}^{n} \,d x } \]
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Timed out. \[ \int (d \sec (e+f x))^m (a+b \tan (e+f x))^n \, dx=\int {\left (\frac {d}{\cos \left (e+f\,x\right )}\right )}^m\,{\left (a+b\,\mathrm {tan}\left (e+f\,x\right )\right )}^n \,d x \]
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